Respuesta :
Answer:
Since, by the quadratic formula,
The solution of a quadratic equation [tex]ax^2+bx+c=0[/tex] is,
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Here, the given quadratic equation,
[tex]5-10x-3x^2=0[/tex]
[tex]-3x^2-10x+5=0[/tex]
By the above formula,
[tex]x=\frac{-(-10)\pm \sqrt{(-10)^2-4\times -3\times 5}}{2\times -3}[/tex]
[tex]=\frac{10\pm \sqrt{100+60}}{-6}[/tex]
[tex]=\frac{10\pm \sqrt{160}}{-6}[/tex]
[tex]=\frac{5\pm 2\sqrt{10}}{-3}[/tex]
[tex]\implies x=-\frac{5+2\sqrt{10}}{3}\text{ or }x=-\frac{5-2\sqrt{10}}{3}[/tex]