[tex]97!=97\times 96\times 95\ldots 3\times 2\times 1[/tex]OR[tex]97!=1\times 2\times 3\ldots 95\times 96\times 97[/tex]
It could be defined as the recursive function [tex]n!=n\times(n-1)!\text{, such that }n\geq 0[/tex]
The final answer is 96192759682482119853328425949563698712343813919172976158104477319333745612481875498805879175589072651261284189679678167647067832320000000000000000000000
