Respuesta :
Scenario 1:
Mass of each of water, brick, iron, and plastic = 1 kg = 1000 g
Specific heat of water = 4.19 J/g⋅∘C
To raise the temperature of 1 g of water by 1∘C the heat required is 4.19 J
Therefore, to raise the temperature of 1000 g of water by 1∘C the heat required is 4.19 x 1000 = 4190 J
Specific heat of brick = 0.90 J/g⋅∘C
To raise the temperature of 1 g of brick by 1∘C the heat required is 0.9J
Therefore, to raise the temperature of 1000 g of brick by 1∘C the heat required is 0.90 x 1000 = 900 J
Specific heat of iron = 0.46 J/g⋅∘C
To raise the temperature of 1 g of iron by 1∘C the heat required is 0.46 J
Therefore, to raise the temperature of 1000 g of iron by 1∘C the heat required is 0.46 x 1000 = 460 J
Specific heat of plastic = 1.01 J/g⋅∘C
To raise the temperature of 1 g of plastic by 1∘C the heat required is 1.01 J
Therefore, to raise the temperature of 1000 g of plastic by 1∘C the heat required is 1.01 x 1000 = 1010 J
So it takes the greatest amount of heat in Joules to raise the temperature of water, followed by plastic, followed by brick and iron.
Now all of them are heated for an equivalent amount of time as a result water will have the lowest resulting or final temperature. The resulting or final temperature of plastic will be greater than water. The resulting or final temperature of brick will be greater than plastic. . The resulting or final temperature of iron will be greater than brick.
Water plastic brick iron
(lowest resulting temperature) --> (highest resulting temperature)
