Respuesta :
Hi there!
Let's let y = x^2
Substitute y into the equation
y^2 + 6y - 7
Now, we need two factors of -7 that add up to 6
-1 and 7 should work
Now, factor
(y - 1)(y + 7)
Substitute y=x^2 back into the equation
(x^2 - 1)(x^2 + 7)
Edit: Garydesir1 made an important note. (x^2 - 1) can be factorized into (x+1)(x-1)
Your full factorization is (x-1)(x+1)(x^2 + 7)
Have an awesome day! :)
Let's let y = x^2
Substitute y into the equation
y^2 + 6y - 7
Now, we need two factors of -7 that add up to 6
-1 and 7 should work
Now, factor
(y - 1)(y + 7)
Substitute y=x^2 back into the equation
(x^2 - 1)(x^2 + 7)
Edit: Garydesir1 made an important note. (x^2 - 1) can be factorized into (x+1)(x-1)
Your full factorization is (x-1)(x+1)(x^2 + 7)
Have an awesome day! :)
Hello there!
The answer is: (x + 1)(x -1)(x² + 7)
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Well, I am not sure how to explain this. But what you need to realize is that you have x^4. It means that you gonna need two x in the left and one x^2 on the right side.
I hope this help!
The answer is: (x + 1)(x -1)(x² + 7)
----------------------------------------------------
Well, I am not sure how to explain this. But what you need to realize is that you have x^4. It means that you gonna need two x in the left and one x^2 on the right side.
I hope this help!