Is each line parallel, perpendicular, or neither parallel nor perpendicular to the line x + 2y = 6?

Drag each choice into the boxes to correctly complete the table

y= -1/2x+5
-2x+y=-4
-x+2y=2
x+2y=-2

Respuesta :

y=-1/2x+5 is parallel.
-2x+y=-4 is perpendicular.
-x+2y=2 is neither.
x+2y=2 is parallel.
Hope this helps

ANSWER

We need to rewrite [tex]x+2y=6[/tex], in slope intercept form.

[tex]\Rightarrow 2y=-x+6[/tex],

[tex]\Rightarrow y=-\frac{1}{2}x+3[/tex]


The given equation has a slope of [tex]-\frac{1}{2}[/tex].

ANSWER TO QUESTION 1

We now the write given options also in slope intercept form.


For the first one, we have

[tex]y=-\frac{1}{2}x+5[/tex]


This first equation also has a slope  of [tex]-\frac{1}{2}[/tex].


Hence [tex]y=-\frac{1}{2}x+5[/tex] is parallel to [tex]x+2y=6[/tex].


ANSWER TO QUESTION 2:

The second equation is;

[tex]-2x+y=-4[/tex].


We need to write this one too in slope intercept form.


[tex]y=2x-4[/tex]


This second equation has a slope of 2

Since [tex]2\times -\frac{1}{2}=-1[/tex], the line [tex]-2x+y=-4[/tex]

is perpendicular to [tex]x+2y=6[/tex].



ANSWER TO QUESTION 3

We rewrite the equation [tex]-x+2y=2[/tex] in slope intercept form.


[tex]\Rightarrow 2y=x+2[/tex]


[tex]\Rightarrow y=\frac{1}{2}x+1[/tex]


This equation also has a slope of [tex]\frac{1}{2}[\tex]

since the slope of [tex]-x+2y=2[/tex] is not equal to the slope of [tex]x+2y=6[/tex], and the product of these two slopes [tex]\frac{1}{2} \times - \frac{1}{2} \ne -1[/tex], the two lines are neither parallel nor perpendicular.



QUESTION 4

The given line has equation [tex]x+2y=-2[/tex]. We rewrite this equation in the slope intercept form.

[tex]\Rightarrow 2y=-x-2[/tex]


[tex]\Rightarrow y=-\frac{1}{2}x-1[/tex]


This line has a slope of [tex]-\frac{1}{2}[/tex].


Since this slope is the same as the slope of the given line,


[tex]y=-\frac{1}{2}x-1[/tex] is parallel to  [tex]x+2y=6[/tex].


See graph in attachment.








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