Respuesta :
y=-1/2x+5 is parallel.
-2x+y=-4 is perpendicular.
-x+2y=2 is neither.
x+2y=2 is parallel.
Hope this helps
-2x+y=-4 is perpendicular.
-x+2y=2 is neither.
x+2y=2 is parallel.
Hope this helps
ANSWER
We need to rewrite [tex]x+2y=6[/tex], in slope intercept form.
[tex]\Rightarrow 2y=-x+6[/tex],
[tex]\Rightarrow y=-\frac{1}{2}x+3[/tex]
The given equation has a slope of [tex]-\frac{1}{2}[/tex].
ANSWER TO QUESTION 1
We now the write given options also in slope intercept form.
For the first one, we have
[tex]y=-\frac{1}{2}x+5[/tex]
This first equation also has a slope of [tex]-\frac{1}{2}[/tex].
Hence [tex]y=-\frac{1}{2}x+5[/tex] is parallel to [tex]x+2y=6[/tex].
ANSWER TO QUESTION 2:
The second equation is;
[tex]-2x+y=-4[/tex].
We need to write this one too in slope intercept form.
[tex]y=2x-4[/tex]
This second equation has a slope of 2
Since [tex]2\times -\frac{1}{2}=-1[/tex], the line [tex]-2x+y=-4[/tex]
is perpendicular to [tex]x+2y=6[/tex].
ANSWER TO QUESTION 3
We rewrite the equation [tex]-x+2y=2[/tex] in slope intercept form.
[tex]\Rightarrow 2y=x+2[/tex]
[tex]\Rightarrow y=\frac{1}{2}x+1[/tex]
This equation also has a slope of [tex]\frac{1}{2}[\tex]
since the slope of [tex]-x+2y=2[/tex] is not equal to the slope of [tex]x+2y=6[/tex], and the product of these two slopes [tex]\frac{1}{2} \times - \frac{1}{2} \ne -1[/tex], the two lines are neither parallel nor perpendicular.
QUESTION 4
The given line has equation [tex]x+2y=-2[/tex]. We rewrite this equation in the slope intercept form.
[tex]\Rightarrow 2y=-x-2[/tex]
[tex]\Rightarrow y=-\frac{1}{2}x-1[/tex]
This line has a slope of [tex]-\frac{1}{2}[/tex].
Since this slope is the same as the slope of the given line,
[tex]y=-\frac{1}{2}x-1[/tex] is parallel to [tex]x+2y=6[/tex].
See graph in attachment.
