Question

find the 5th term sequence defined as : a(n)=(n+3)∧n-1

Answer 1

$a_n=(n+3)^n-1\\\\a_1=(1+3)^1-1=4-1=3\\\\a_2=(2+3)^2-1=5^2-1=25-1=24\\\\a_3=(3+3)^3-1=6^3-1=216-1=215\\\\a_4=(4+3)^4-1=7^4-1=2401-1=2400\\\\a_5=(5+3)^5-1=8^5-1=32768-1=32767$