A line has a slope of mc013-1.jpg and passes through the point (–5, 4). Which is the equation of the line?

Answer:
y = [tex]\frac{-3x}{4}[/tex] + [tex]\frac{1}{4}[/tex].
Step-by-step explanation:
Given : Graph of slope [tex]\frac{-3}{4}[/tex] and passes through the point (–5, 4).
To find : Which is the equation of the line.
Solution : we have given that point ( -5 ,4)
By equation of line ([tex]y-y_{1}) = m (x -x_{1})[/tex]
y - 4 = [tex]\frac{-3}{4}[/tex]( x +5).
y - 4 = [tex]\frac{-3x}{4}[/tex] +[tex]\frac{-15}{4}[/tex].
On adding 4 both sides we get,
y = [tex]\frac{-3x}{4}[/tex] + [tex]\frac{-15}{4}+4[/tex].
y = [tex]\frac{-3x}{4}[/tex] + [tex]\frac{-15 +16}{4}[/tex].
y = [tex]\frac{-3x}{4}[/tex] + [tex]\frac{1}{4}[/tex].
Therefore, y = [tex]\frac{-3x}{4}[/tex] + [tex]\frac{1}{4}[/tex].