Question

What mass of manganese (II) chloride must react with sulfuric acid to release 49.5 mL of hydrogen chloride gas at STP? MnCl2(s) + H2SO4(aq)-->MnSO4(aq) + 2HCl(g)

Answer 1

The mass of the manganese II chloride or Mncl2 must react with the sulfuric acid to release the 49.5 mL of hydrogen chloride gas at STP;
(0.0495L HCl) / (22.414 L/mol) x (1 mol MnCl2 / 2 mol HCl) x (125.8440 g MnCl2/mol) = 0.1389595342 approximately 0.139 g MnCl2
The mass of the manganese II chloride or Mncl2 will be 0.139 g MnCl2

Answer 2

Using the balanced reaction equation and stoichiometry, tha mass of MnCl2 is 0.14 g.

What is chemical reaction?

The term chemical reaction refers to the interaction between reactants to yield products. The reaction equation is; MnCl2(s) + H2SO4(aq)-->MnSO4(aq) + 2HCl(g)

1 mole of HCl gas occupies 22400mL

x moles of HCl occupies 49.5 mL

x = 0.0022 moles

Now;

1 mole of MnCl2 yields 2 moles of HCl

x moles MnCl2 yields  0.0022 moles molesof HCl

x = 0.0011 moles

Mass of MnCl2  = 0.0011 moles * 126 g/mol = 0.14 g

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