Question

A test has a mean of 80 and standard deviation of 4. what score would be 1 deviation from the mean

Answer 1

Any score between 76 and 84 will be 1 deviation from the mean.

To figure this out you subtract 4 from 80 (80-4 = 76) and you add 4 to 80 (80+4) = 84 and that tells you that most of the scores will fall between 76 and 84 which is 1 deviation from the mean. 

Answer 2

Test has a mean of 80 and standard deviation of 4 than after one deviation from the mean, most of the score will fall in the interval ($\mu - \sigma\;,\; \mu + \sigma$) which is (76 , 84).

Given :

Mean, $\mu = 80$

Standard Deviation, $\sigma = 4$

After one deviation from the mean, most of the score will fall in the interval ($\mu - \sigma\;,\; \mu + \sigma$). Where $\mu$ is the mean which is arithmetic average of all values and $\sigma$ is the standard deviation which is the square root of its variance.

Now, the value of  $\mu - \sigma = 80-4 = 76$.

And the value of  $\mu + \sigma = 80+4=84$.

After one deviation from the mean, most of the score will fall in the interval ($\mu - \sigma\;,\; \mu + \sigma$) which is (76 , 84).

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https://brainly.com/question/13336998