Question

» Accelerating Lear Jet

Mike is piloting a lear jet traveling at 193.8 m/s. He accelerates at 13.5 m/s2 over a distance of 2370 meters. How fast will the jet be moving at the end of this acceleration

Answer 1

The equation relevant to use here is:

v^2 = v0^2 + 2 a d

where,

v is final velocity = ?

v0 is intial velocity = 193.8 m/s

a is acceleration = 13.5 m/s^2

d is distance = 2370 m

 

v = sqrt [193.8^2 + 2 (13.5) 2370]

v = 318.67 m/s