Question

WILL MARK BRAINLIEST!!
Write log3 6 as a logarithm of base 2.

log base 2 of 3 over log base 2 of 6
log base 2 of 6 over log base 2 of 3
log base 3 of 2 over log base 6 of 2
log base 6 of 2 over log base 3 of 2

Answer 1

The answer is the second option. (log2)6/(log2)3.

Using the change-of-base formula: 
log3(x)=logb(x)/logb(a)

 to write log3(6) as a logarithm of base 2: a = 3, x = 6, b = 2:

log3(6)=log2(6)/log2(3)


hope this helps ^-^

Answer 2

Answer:

Option 2 - log base 2 of 6 over log base 2 of 3

Step-by-step explanation:

Given : Expression $\log_3 6$

To find : Write the expression as a  logarithm of base 2?

Solution :

Expression $\log_3 6$

Applying the change-of-base formula,

$\log_a(x)= \frac{\log_b(x)}{\log_b(a)}$

On comparing, a = 3, x = 6, b = 2

Substitute in the formula,

$\log_3 (6)= \frac{\log_2(6)}{\log_2(3)}$

Therefore, Option 2 is correct.

Option 2 - log base 2 of 6 over log base 2 of 3