Question

Find m <ABC (7x-1) (3x-9

Answer 1

(7x-1)+(3x-9)=180
10x-10=180
Add 10 to both sides
10x=170
Divide both sides by 10
X=17 degrees

3x-9
3(17)-9
51-9
=48

Answer 2

Answer:

Therefore, $\angle ABC = 48\degree$

Step-by-step explanation:

We need to find the $\angle ABC$

Since, $\angle DBC = 180\degree$      ( since DBC is straight line )

$(7x-1)+(3x-9)=180\degree$

$10x-10=180 \degree$

Add both the sides by 10 in above expression

$10x-10+10=180\degree+10$

$10x=180 \degree+10$

$10x=190 \degree$

divide both the sides by 10 in above expression

$x=\frac{190}{10}$

$x=19$

Hence, the value of x is 19.

Now, we will calculate $\angle ABC$

$\angle ABC = 3x-9$

Put x = 19 in above

$\angle ABC = 3(19)-9$

$\angle ABC = 57-9$

$\angle ABC = 48$

Therefore, $\angle ABC = 48$.