Question

In the figure, sin ∠MQP = ______.

A. Cos N and Sin R
B. Sin R and Sin N
C. Cos N and Sin M
D. Cos R and Sin N

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Answer 1

Sin N  = NM/NR
Cos R  = NM/NR

so answer is 
D. Cos R and Sin N

Answer 2

we know that

in the right triangle MNR

$Sin(N\°)=Cos(R\°)$

$Sin(56\°)=Cos(34\°)$

Because

$N+R=90\°$

$56\°+34\°=90\°$ --------> by complementary angles

so

sin ∠MQP=$Sin(56\°)$

therefore

the answer is the option

D. Cos R and Sin N