Respuesta :
60
D>0, there are 2 distinct real roots
Explanation:
3x2+6x−2=0
a=3,b=6,c=−2
The formula for discriminant is b2−4acSubstitute the given values.
b2−4ac
(6)2−4(3)(−2)
=60
therefore, D>0, there are 2 distinct real roots
D>0, there are 2 distinct real roots
Explanation:
3x2+6x−2=0
a=3,b=6,c=−2
The formula for discriminant is b2−4acSubstitute the given values.
b2−4ac
(6)2−4(3)(−2)
=60
therefore, D>0, there are 2 distinct real roots
Discriminant, not discrimination. I'm not discriminating against you. ;)
You must re-write 3x^2+6x=2 in standard form: 3x^2 + 6x - 2
Here a=3, b=6 and c= -2
The discriminant is b^2 - 4ac. Here, it's 6^2 - 4(3)(-2), or 36 + 24, or 60.
This quadratic has two real, unequal, zeros.
You must re-write 3x^2+6x=2 in standard form: 3x^2 + 6x - 2
Here a=3, b=6 and c= -2
The discriminant is b^2 - 4ac. Here, it's 6^2 - 4(3)(-2), or 36 + 24, or 60.
This quadratic has two real, unequal, zeros.