The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. Find the width and length.

Respuesta :

let the width = x
=>length = 2x-1

91= x(2x-1)=2x^2-x
2x^2-x-91=0
=(2x+13)(x-7)
=> x=-13/2=> no
=>x= 7 cm

The length of the photograph is 13 cm and the width is 7 cm.

What is a rectangle?

A rectangle is a quadrilateral having the four sides and the sum of the angles is 180 in the rectangle the opposite two sides are equal and parallel and the two sides are at 90-degree angles.

Given that:-

  • The length of a photograph is 1 cm less than twice the width
  • The area is 91 cm²

The length and the width will be calculated as:-

let the width = x

length = 2x  -  1

91  =  x  (  2x  -  1  )  =  2x² - x

2x² -  x  -  91  =   0

=  ( 2x  +  13  )  (  x   -  7 )

x  =  - 13  /   2

x  = 7 cm

Length will be  = 2x  -  1 =  2  x  7  -  1  =  13 cm

Therefore the length of the photograph is 13 cm and the width is 7 cm.

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