Answer: The correct option is 3 ohms.
Solution:
When resistors are connected in parallel the total resistance is given by :
[tex]\frac{1}{R_{total}}=\sum_{i=1}^n\frac{1}{R_1}+\frac{1}{R_2}+...\frac{1}{R_n}[/tex]
[tex]R_1=12 ohm[/tex]
[tex]R_2=4 ohm[/tex]
[tex]\frac{1}{R_{total}}=\frac{1}{12}+\frac{1}{4}=3 ohm[/tex]
The total resistance of the two devices is 3 ohm .