Question

WILL MARK BRAINLIEST!
A sample was taken of dogs at a local dog park on two random days. The counts are displayed in the table below. If there are estimated to be 50 dogs at the park at any given time, which proportion could be used to find the average number of shepherd mixes at the park at any given time?

Answer 1

Answer:

⇒$\frac{8}{21} =\frac{x}{50}$

Step-by-step explanation:

Let average no. of shepherds be x

there are estimated to be 50 dogs

Thus average no. of dogs /  estimated no. of dogs =x/50

Since in sample 1 there are 7 shepherd mix

In sample 2 there are 9 shepherd mix

So total shepherd mix = 9+7=16

Total dogs according to table = 4+7+3+1+2+5+9+5+2+4=42

Thus total shepherd / total dogs = 16/42

A.T.Q

$\frac{16}{42} =\frac{x}{50}$

⇒$\frac{8}{21} =\frac{x}{50}$

This proportion  could be used to find the average number of shepherd mixes at the park at any given time

Thus option A is correct

Answer 2

The average number of shepherd mixes at the park at any given time is equal to $\frac{8}{21} =\frac{x}{50}$.

• Let the average number of shepherd mixes be x.

Given the following data:

• Estimated population = 50 dogs.

To determine the average number of shepherd mixes at the park at any given time:

How to calculate the shepherd mixes.

First of all, we would determine the total number of shepherd mixes in sample 1 and sample 2.

Total shepherd mixes = $7 + 9$ = 16 dogs.

For the total dogs:

Total dogs = $4+1+7+3+2+5+9+5+2+4$ = 42 dogs.

The average number of shepherd mixes is given by this mathematical expression:

$\frac{16}{42} =\frac{x}{50}$

Simplifying further, we have:

$\frac{8}{21} =\frac{x}{50}$

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