Question

G a person of mass 100 kg is riding an elevator which was initially moving up with a velocity of 3 m/s. over a distance of 4 m the elevator slows down to 1 m/s. find the "apparent" mass of the person during that time (as the elevator slows down).

Answer 1

E=mc² where c is speed of the light
3 m/s more andmore less than speed of the light. So mass of the person still 100 kg