Question

What is the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30c?

Answer 1

Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)

.6 = n(2519.142)

Divide by 2519.142

n = .00023818 mols of HCl * 36.46g of HCl/ 1 mol of HCl

Grams of HCl = 0.00868