Question

Given the quadratic function 3x^(2) =8x-5 what are the values of x?

Answer 1

3x^2 = 8x - 5

3x^2 - 8x + 5 = 0    move all terms to one side

3x^2 - 3x - 5x + 5 = 0  split them into two terms

3x(x - 1) - 5(x - 1) = 0   factor out common terms in the first two terms, then the last two terms.

(x - 1)(3x - 5) = 0

x = 1, 5/3

hope this helped, God bless!

Answer 2

Answer:

The values of x are $\frac{5}{3}$ and 1.

Step-by-step explanation:

Given quadratic function$3x^2=8x-5$

We have to solve for x.

Consider the given quadratic function $3x^2=8x-5$

This can be written as $3x^2-8x+5=0$

We can solve the above quadratic equation using middle term split method,

-8x can be written as -3x - 5x

Thus, the equation becomes,

$3x^2-8x+5=0$

$\Rightarrow 3x^2-3x-5x+5=0$

Taking 3x common from first two term and -5 common from last two terms, we get,

$\Rightarrow 3x(x-1)-5(x-1)=0$

$\Rightarrow (3x-5)(x-1)=0$

Now using zero product property $a.b=0 \Rightarrow a=0\ or\ b=0$ , we have,

$\Rightarrow (3x-5)=0$ or $\Rightarrow (x-1)=0$

$\Rightarrow x=\frac{5}{3}$ or $\Rightarrow x=1$

Thus, The values of x are $\frac{5}{3}$ and 1.