Question

what is( -10a^5-2a^5+14a^5)(12a^5-6a-10a^3)

using distributive and the area model.

Answer 1

$(-10a^5-2a^5+14a^5)(12a^5-6a-10a^3) \\ = 2a^5 (12a^5-6a-10a^3) \\ = 24a^{10} - 12a^6 - 20a^8$