[tex]\bf P(\stackrel{a}{8}~,~\stackrel{b}{6})\impliedby \textit{let's find the hypotenuse}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+6^2}\implies c=\sqrt{64+36}\implies c=\sqrt{100}\implies c=10
\\\\\\
sin(\theta)=\cfrac{\stackrel{b}{opposite}}{\stackrel{c}{hypotenuse}}\implies sin(\theta )=\cfrac{6}{10}\implies sin(\theta )=\cfrac{3}{5}[/tex]
