Question

One of the zeros of the polynomial function is 2.
 

f(x)=x4−3x3−23x2+75x−50

What is the factored form of the function?

 

f(x)=(x−5)(x+5)(x−2)2f(x)=(x−5)(x+5)(x−2)(x−1)f(x)=(x−5)(x+5)(x−2)(x+1)f(x)=(x−5)(x+5)(x−1)2

Answer 1

Answer:

Heres the correct answer. Hope this helps anyone who needs it!!!

Step-by-step explanation:

Answer 2

The polynomial function is one that involves only non-negative number powers of x, unlike a polynomial, cubic, or quartic function, and further calculation can be defined as follows:

Given:

$\bold{f(x)=x^4-3x^3-23x^2+75x-50}$

To find:

Solution:

$\to \bold{f(x)=x^4-3x^3-23x^2+75x-50}$

Let $\bold{x=2}$

$\to \bold{f(2)=2^4-3(2)^3-23(2)^2+75(2)-50}\\\\\to \bold{f(2)=16-3(8)-23(4)+75(2)-50}\\\\\to \bold{f(2)=16-24-92+150-50}\\\\\to \bold{f(2)=166-166}\\\\\to \bold{f(2)=0}$

So the factor is $\bold{(x-2)}$.

$\to \bold{(x-5)(x-2)(x-1)(x+5)}$

Therefore, the final answer is "$\bold{ f(x)=(x-5)(x-2)(x-1)(x+5)}$".

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brainly.com/question/2511359