Respuesta :
Check the picture:
Rotating JKL 180° with respect to the origin, and translating it 1 unit up, we get J'K'L'.
That is, the 2 triangles match perfectly.
Answer:
△JKL is congruent to △J′K′L′ because you can map △JKL to △J′K′L′ using a rotation of 180° about the origin followed by a translation 1 unit up, which is a sequence of rigid motions.
Rotating JKL 180° with respect to the origin, and translating it 1 unit up, we get J'K'L'.
That is, the 2 triangles match perfectly.
Answer:
△JKL is congruent to △J′K′L′ because you can map △JKL to △J′K′L′ using a rotation of 180° about the origin followed by a translation 1 unit up, which is a sequence of rigid motions.

Answer:
As Given :The coordinates of the vertices of △JKL are J(3, 0) , K(1, −2) , and L(6, −2) . The coordinates of the vertices of △J′K′L′ are J′(−3, 1) , K′(−1, 3) , and L′(−6, 3) .
⇒As we can see the two triangles are congruent because length of sides are equal.i.e By SSS ΔJKL and ΔJ'K'L' are congruent.
⇒ As you can see from the figure depicted below the triangle JKL is rotated by an angle of 180° then translation of y coordinate by 1 unit up has taken place.
So , Option (3) is correct which is :△JKL is congruent to △J′K′L′ because you can map △JKL to △J′K′L′ using a rotation of 180° about the origin followed by a translation 1 unit up, which is a sequence of rigid motions.

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