Question

Write chemical equation for second step of a born - haber cycle. bai2

Answer 1

* Atomisation (sublimation) Energy of Barium (endo) Ba(s) --> Ba(g) * Sum of 1st and 2nd Ionisation Energies of barium (endo) Ba(g) --> Ba+(g) --> Ba2+(g) * Atomisation energy of iodine (endo) I2(s) --> 2I(g) * Twice the electron affinity of iodine (exo) 2I(g) --> 2I-(g) * Lattice enthalpy of barium iodide (exo) Ba2+(g) + 2I-(g) ---> BaI2(s)

Answer 2

Answer:

The second step is the atomization (sublimation) of Ba

Ba(s) → Ba(g)

Explanation:

The Born Haber cycle allows one to determine the lattice energy of an ionic solid. Lattice energy or lattice enthalpy is the enthalpy change when 1  mole of an ionic solid is formed from its gaseous ions.

In the given example of BaI2 the corresponding steps as per the Born Haber cycle would be:

Step 1) Enthalpy of Formation of BaI2

Ba(s) + I2(s) → BaI2 (s)

Step 2) Atomization of Ba

Ba(s) → Ba(g)

Step 3) Atomization of I2

I2(s) → I2(g)

Step4) IOnization of Ba(g)

Ba(g) → Ba2+(g) + 2e-

Step 5) Electron affinity of I2

I2(g) + 2e- → 2I-(g)

Step 4) Lattice energy of BaI2

Ba2+ (g) + 2I-(g) → BaI2