Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and the density of the gas is 0.710 g/cm3, how many kilograms of fuel are contained in one canister?

Respuesta :

the canister contains a gas used to fuel a burner

the volume of the white gas to be used is - 1.45 L

density of white gas is 0.710 g/cm³

density is defined as the mass per unit volume

the mass of 1 cm³ of white gas is - 0.710 g

1 cm³ is equivalent to 0.001 L

the volume given is in Litres

so if 0.001 L has a mass of 0.710 g

then 1.45 L have a mass of - 0.710 g / 0.001 L x 1.45 L = 1030 g

since 1000 g is equivalent to 1 kg

mass of white fuel is - 1030 g/1000 g/kg = 1.03 kg

theres 1.03 kg of fuel in one canister



The number of  kilograms  of fuel   that are contained in one  canister  is 1.03 Kilograms


calculation

mass =  density x  volume

Density= 0.710 g/cm³

volume = 1.45 L

convert  1.45 l into cm³  to make the units  uniform

that is     1 L= 1000 cm³

              1.45 L=  cm³

by cross  multiplication

= (1.45 L  x 1000 cm³)  / 1 L  = 1450 cm³


mass is therefore =   0.710g/cm³  x 1450 cm³   =1029.5 grams


convert grams to Kg

1 kg = 1000 grams

  ? kg  =1029.5  grams

by cross  multiplication

= (1 kg  x 1029.5 grams) /1000 grams  = 1.0295 Kg ≅1.03 kg



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