Question

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. If this player shoots twice, the exact probability that he scores a goal both times is

Answer 1

If he misses 63%, then he makes it 37% each time he shoots.
To calculate the probability if he makes it both times, you multiply it together:
37% * 37% = 13.69%

Answer 2

Answer:

The probability of scoring two goals in both times is 0.137 or 13.7%

Step-by-step explanation:

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.

So $P(A)=0.63$

Hence, the probability of getting success in his shoots will be,

$P(A^c)=1-P(A)=1-0.63=0.37$

The probability of scoring two goals in both times is,

$=P(A^c)\cdot P(A^c)$

$=0.37\times 0.37$

$=0.137$

$=13.7\%$