Question

What is the best order-of-magnitude estimate for 0.00003?
a. 10-3
b. 10-4
c. 10-5
d. 10-6

Answer 1

$0\underbrace{.00003}_{\to5\ places}=3\cdot10^{-5}\to estimate\ \boxed{10^{-5}}\leftarrow\boxed{c.}$

$because\ 3 \ \textless \ 5\ ;)$