Question

PLEASE HELP ME!!!! WORTH 10 POINTS!!
Write the point-slope form of the given line that passes through the points (-4, -1) and (3, -3). Identify (x1, y1) as (-4, -1).Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answer 1

(-4, -1) and (3, -3)

slope m = (-3 + 1) /(3 + 4) = -2/7

y - y1 = m(x - x1)
(x1, y1) as (-4, -1)

equation
y + 1 = -2/7(x +4)

Answer 2

Answer:

$y-(-1)=-\frac{2}{7}(x-(-4))$

Step-by-step explanation:

We know that the line passes through (-4,-1) and (3,-3), where $(x_{1} ,y_{1} )$ is $(-4,-1)$ and $(x_{2} ,y_{2} )$ is $(3,-3)$.

First, we need to find the slope with the formula

$m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Replacing given points

$m=\frac{-3-(-1)}{3-(-4)}=\frac{-3+1}{3+4}=\frac{-2}{7}$

Then, we use the slope, one point and the slope-point form

$y-y_{1} =m(x-x_{1} )\\y-(-1)=-\frac{2}{7}(x-(-4))\\ y+1=-\frac{2}{7}x+\frac{8}{7} \\y=-\frac{2}{7}x+\frac{8}{7}-1\\y=-\frac{2}{7}x+\frac{8-7}{7} \\y=-\frac{2}{7}x+\frac{1}{7}$

The slope-intercept form is

$y=-\frac{2}{7}x+\frac{1}{7}$

The point-slope form is

$y-(-1)=-\frac{2}{7}(x-(-4))$