Complete the pairs of 's.
(triangle)FCA ~= (triangle)
DAC
EBC
GCA
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Answer:
DAC
Step-by-step explanation:
We can write, from the figure of the question.
In ΔFCA and ΔDAC.
∠FAC=∠DCA,
AC=CA, (common)
∠FCA=∠DAC.
Hence , we can say ΔFCA ≅ ΔDAC, because here in ΔFCA and ΔDAC, the two corresponding angles and including side are same (from ASA postulate ).