Respuesta :

Suppose you are given a quadratic equation with vertex (h, k) and y-intercept, c.

The vertex form of a quadratic equation is given by:

[tex]y=a(x-h)^2+k=ax^2-2ahx+ah^2+k[/tex]

y-intercept is the value of y when x is 0.

Thus, given a y-intercept, c, we have:

[tex]c=ah^2+k \\ \\ \Rightarrow ah^2=c-k \\ \\ \Rightarrow a= \frac{c-k}{h^2} [/tex]

Therefore, given a vertex (h, k) and y-intercept, c, the quadratic equation is given by

[tex]y=\left(\frac{c-k}{h^2}\right)x^2-2\left(\frac{c-k}{h^2}\right)hx+\left(\frac{c-k}{h^2}\right)h^2+k \\ \\ =\left(\frac{c-k}{h^2}\right)x^2-2\left(\frac{c-k}{h}\right)x+c-k+k \\ \\ =\bold{\left(\frac{c-k}{h^2}\right)x^2-2\left(\frac{c-k}{h}\right)x+c}[/tex]
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