72.45
Since 67.36% is greater than 50%, we know that the cutoff will be at a negative value. And we need to lookup in a standard normal table for the value of 67.36 - 50 = 17.36. That value will happen with a z value of 0.45. Now multiply the standard deviation of 9 by 0.45 to get 4.05. That means that the cutoff value for the student getting a C or above is the mean minus 4.05, so 76.5 - 4.05 = 72.45