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The dna strand consists of eight pairs of nitrogenous bases. how many different sequences of eight basescan you make?

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There are four nitrogenous bases that makes DNA. These are A, T, G and C. If a DNA strand has eight pairs of nitrogenous bases, the eight bases can be
1. AA GG TT CC
2. GC GG AT CG
3. AT TA GG GC
4. GA AG GC GG
Like this, there can be 65,536 different sequences with ATCG.
Since we have 4 nitrogenous bases, pairing will make 4 X 4 = 16 combinations. If we have to make 8 pairs of bases, the number of possible sequences would be 4 to the power 8.

Answer: THERE WILL BE 65,536 DIFFERENT SEQUENCES OF 8 BASES.

DNA is made up of four nitrogenous nucleotides. The purines are Adenine(A) and Guanine (G) while the pyrimidine present in the DNA are Cytosine (C) and Thymine (T).

65,536 different sequences can be made.

The eight bases of a DNA strand with pairs of nitrogenous nucleotides formed can be:

1. AA GG TT CC

2. GC GG AT CG

3. AT TA GG GC

4. GA AG GC GG

Sequence can be calculated by:

  • Pairing will result in 4 X 4 = 16 options because we have four nitrogenous bases.

  • The number of potential sequences is 4⁸ if we have to make 8 pairs of bases.

Thus, there will be a total of 65,536 different sequences of eight bases.

To learn more about DNA follow the given link:

https://brainly.com/question/13695548

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