The ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. in the first step of the ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. what is the maximum mass of h2o that can be produced by combining 51.3 g of each reactant?
4 NH3 + 5 O2 ----> 4 NO + 6 H2O
4 moles of ammonia (4 * 17.03 g/mol) will react with 5 moles of oxygen (5 * 32.00 g/mol) to give 6 moles of water (6 * 18.02 g/mol).
This means that 68.12 grams of ammonia will react with 160.0 grams of oxygen to yield 108.12 grams of water. If only 75.6 grams of oxygen are available then:
75.6 g / 160.0 g/mol = 0.47 mol of oxygen is used.
