Answer:
The solution of given inequality is x ≥1.
Step-by-step explanation:
The given inequality is
[tex]10x+16\geq 6x+20[/tex]
We need to separate the variable terms to solve the above inequality.
Subtract 6x and 16 from both sides to separate the variables on left side.
[tex]10x+16-6x-16\geq 6x+20-6x-16[/tex]
On combining like terms we get
[tex](10x-6x)+(16-16)\geq (6x-6x)+(20-16)[/tex]
[tex]4x\geq 4[/tex]
Divide both sides by 4.
[tex]x\geq \frac{4}{4}[/tex]
[tex]x\geq 1[/tex]
Therefore the solution of given inequality is x ≥1.
