Question

The perimeter of a triangle is 7272 cm. the longest side is 66 cm less than the sum of the other two sides. twice the shortest side is 55 cm less than the longest side. find the length of each side of the triangle.

Answer 1

suppose the three sides are a, b, and c, with c being the longest, a being the shortest
first equation: c=(a+b)-66
second equation: 2a=c-55=> c=2a+55
plug c=2a+55 into the first equation: 2a+55= a+b-66 => b=a+121
a+b+c=a+(a+121)+(2a+55)=7272 =>4a+176=7272 =>a=1774
a=1774, b=1895, c=3603