Question

What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 13 ?
A)y−2=13(x−6)
B) y+6=13(x+2)
C) y−6=13(x−2)
D) y+2=13(x+6)

Answer 1

$\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ -6}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 13 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-6)=13[x-(-2)] \\\\\\ y+6=13(x+2)$