Question

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? plz show me how u got the answer

Answer 1

We can model the problem using a right angle triangle. 

The two sides, AB and BC are equal
By Pythagoras, we find the length of AC = $\sqrt{1^+1^}$ = $\sqrt{2}$

Using the sin ratio ⇒ sin θ = opposite/hypotenuse, we have
$sin(45)= \frac{1}{ \sqrt{2} }= \frac{ \sqrt{2} }{2}$

Using the cos ratio ⇒ cos θ = adjective/hypotenuse, we have
$cos(45)= \frac{1}{ \sqrt{2} }= \frac{ \sqrt{2} }{2}$

Using the tan ratio ⇒ tan θ = opposite/adjective, we have
$tan(45)= \frac{1}{1}=1$