Question

The three seventh grade classes at Sunview Middle School collected the most boxtops for a school fundraiser. They won a $600 prize to share among them. Mr. Aceves’ class collected 3,760 box tops, Mrs. Baca’s class collected 2,301, and Mr. Canyon’s class collected 1,855. How should they divide the money so that each class gets the same fraction of the prize money as the fraction of the box tops that they collected? Explain your reasoning.

Answer 1

Since Mr. Aceve's class collected 3,760 they should receive $300 of the prize money, Mrs. Baca's class collected 2,301 they should receive $200, Mr. Canyon's class collected 1,855 they should receive $100.

Answer 2

Answer: The share would be approximately $285, $175, $141 respectively.

Step-by-step explanation:

Since we have given that

Number of box tops collected by Mr. Aceves's class = 3760

Number of box tops collected by Mrs. Baca's class = 2301

Number of box tops collected by Mr, Canyon's class = 1855

We first find the ration of box tops of Mr. Aceves, Mrs. Baca and Mr. Canyon respectively:

3760:2301:1855

Total = 3760+2301+1855=7916

Total amount to be share among them as a prize = $600

Mr. Aceves's share is given by

$\dfrac{3760}{7916}\times 600\\\\=284.99\\\\\approx 285$

Mrs. Baca's share is given by

$\dfrac{2301}{7916}\times 600\\\\=175.08\\\\\approx 175$

Mr. Canyon's share is given by

$\dfrac{1855}{7916}\times 600\\\\=140.60\\\\\approx 141$

Hence, the share would be approximately $285, $175, $141 respectively.