Question

give me a long equation that equals 7

****first best answer gets 30 points. Hurry though please

Answer 1

One possible equation is:

$\frac{3(6-(4\div 2)^2)+9-2^3}{11-(2\times 5)}$

To double check that this is correct, work from the inside of the numerator out:

$\frac{3(6-(4\div2)^2)+9-2^3}{11-(2\times5)} \\ \\=\frac{3(6-(2)^2)+9-2^3}{11-(2\times5)} \\ \\=\frac{3(6-4)+9-2^3}{11-(2\times5)} \\ \\=\frac{3(2)+9-2^3}{11-(2\times5)} \\ \\=\frac{3(2)+9-8}{11-(2\times5)} \\ \\=\frac{6+9-8}{11-(2\times5)} \\ \\=\frac{7}{11-(10)} \\ \\=\frac{7}{1}=7$