Question

1. In a population of 200 field mice, 98 mice are homozygous dominant for brown fur (FF), 84 mice are heterozygous (Ff), and 18 mice are homozygous recessive and have white fur (ff).

A. What are the genotype frequencies of this mice population?

FF =

Ff =

ff =

B. What are the allele frequencies of this population?

F allele =

f allele =

Answer 1

A.
The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals. 
FF genotype frequency:
98÷200=0,49. There are approximately 5 homozygous dominant mice in 10.
Ff genotype frequency:
84÷200=0,42. There are approximately 4 heterozygous mice in 10.
ff genotype frequency:
18÷200=0,09. There are approximately 1 homozygous recessive mouse in 10.

B.
To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
$\frac{(98*2)+84}{400}$=0.7
There are 7 F alleles in 10 random alleles.
f allele frequency:
$\frac{84+(18*2)}{400}$=0.3
There are 3 f alleles in 10 random alleles.