Respuesta :
To find the inverse swap the x and y values....
f ( x) = 7x - 1
Start by replacing f(x) by ... y
y = 7x - 1
Now swap both x and y values....
x = 7y - 1
Solve for x...
x = 7y - 1
+1 +1
x+ 1 = 7 y
Divide both sides by 7
x/ 7 + 1/7 = y
Now that we have our inverse you using the f(x) inverse notation..
which is ... f(x) ^-1
So the inverse of this function is... f(x)^-1 = x/7 + 1/7
f ( x) = 7x - 1
Start by replacing f(x) by ... y
y = 7x - 1
Now swap both x and y values....
x = 7y - 1
Solve for x...
x = 7y - 1
+1 +1
x+ 1 = 7 y
Divide both sides by 7
x/ 7 + 1/7 = y
Now that we have our inverse you using the f(x) inverse notation..
which is ... f(x) ^-1
So the inverse of this function is... f(x)^-1 = x/7 + 1/7
The inverse of the function f(x) = 7x - 1 is [tex]f^{-1}(x) = \frac{x}{7} + \frac{1}{7}[/tex]
The given function is:
f(x) = 7x - 1
Make x the subject of the formula
[tex]f(x) = 7x - 1\\\\7x = f(x) + 1\\\\[/tex]
Divide through by 7
[tex]\frac{7x}{7}= \frac{f(x)}{7} + \frac{1}{7}\\\\x = \frac{f(x)}{7} + \frac{1}{7}[/tex]
Replace x by [tex]f^{-1}(x)[/tex] and replace f(x) by x:
[tex]f^{-1}(x) = \frac{x}{7} + \frac{1}{7}[/tex]
Therefore the inverse of the function f(x) = 7x - 1 is [tex]f^{-1}(x) = \frac{x}{7} + \frac{1}{7}[/tex]
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