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The answers are as follows:
1. As the size of a cell increases, THE RATIO OF SURFACE AREA TO VOLUME OF THE CELL DECREASES.
A small cell has a large surface area to volume ratio but as this cell increases in size, the ratio begin to decrease until it gets to a point where the cell just has to undergo binary fission in order to increase its surface area to volume ratio.
2. A surface area to volume ratio [SA:V] of 6:1 mean that the cell has a large surface area to volume ratio. This ratio is very important because the survival of the cell depends on it. A cell usually carry out its life maintaining activities through diffusion. If the SA:V ratio is small, the efficiency of diffusion will be low and the cell needs will not be properly met. But if the SA:V ratio is high, the efficiency of the diffusion process will be high and the cell will have all its needs met easily.
3. A surface area to volume ratio of 3:1 is low compared to that of 6:1. A cell will a surface area to volume ratio of 3:1 will have low diffusion rate, this means that the necessary particles that needs to enter the cell and those that need to leave the cell will not be able to diffuse across the cell membrane efficiently and this will cause disruption of activities to occur inside the cell. The SA:V ratio of 6:1 is ideal and it allows for efficient diffusion of particles in and out of the cell.
1. As the size of a cell increases, THE RATIO OF SURFACE AREA TO VOLUME OF THE CELL DECREASES.
A small cell has a large surface area to volume ratio but as this cell increases in size, the ratio begin to decrease until it gets to a point where the cell just has to undergo binary fission in order to increase its surface area to volume ratio.
2. A surface area to volume ratio [SA:V] of 6:1 mean that the cell has a large surface area to volume ratio. This ratio is very important because the survival of the cell depends on it. A cell usually carry out its life maintaining activities through diffusion. If the SA:V ratio is small, the efficiency of diffusion will be low and the cell needs will not be properly met. But if the SA:V ratio is high, the efficiency of the diffusion process will be high and the cell will have all its needs met easily.
3. A surface area to volume ratio of 3:1 is low compared to that of 6:1. A cell will a surface area to volume ratio of 3:1 will have low diffusion rate, this means that the necessary particles that needs to enter the cell and those that need to leave the cell will not be able to diffuse across the cell membrane efficiently and this will cause disruption of activities to occur inside the cell. The SA:V ratio of 6:1 is ideal and it allows for efficient diffusion of particles in and out of the cell.
The ratio of surface area to volume decreases if the cell increases its size.
The ratio of surface area to volume decreases if the cell size increases but no change will occur in its shape because when the cell increase in size it occupy more space which means more volume.
The surface area/volume ratio of 6:1 mean that the cells has ability to get more materials move across its surface due to diffusion. If there is large surface area than more materials and nutrients can diffuse across membrane of the cell and vice versa.
The surface area/volume ratio of 3:1 as compared to the cell with the ratio of 6:1 means that the cell has less surface area and move less materials across the cell membrane as compared to larger surface area/ volume ratio so we can conclude that less substances are diffused from surface area/volume ratio of 3:1 as compared to surface area/volume ratio of 6:1.
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