Respuesta :
x < 9...this is saying the hourly wage is less then 9 (not including 9)
x > = 14...this is saying the hourly wage is 14 and above
so possible values are : 8,14,15 <==
x > = 14...this is saying the hourly wage is 14 and above
so possible values are : 8,14,15 <==
we have
[tex]x<9[/tex] ------> inequality A
The solution of the inequality A is the interval--------> (-∞,9)
All real numbers less than [tex]9[/tex]
[tex]x\geq14[/tex] -----> inequality B
The solution of the inequality B is the interval--------> [14,∞)
All real numbers greater than or equal to [tex]14[/tex]
The solution Inequality A or Inequality B is equal to
Solution A+Solution B
(-∞,9)U[14,∞)
The solution of the compound system of inequalities must satisfy inequality A or inequality B
we're going to verify every case
case A) [tex]\$8[/tex]
Substitute the value of x in the inequality A and in the inequality B to verify
Verify inequality A
[tex]8<9[/tex] -------> is true
Therefore
[tex]\$8[/tex] is a possible value for x
You don't need to check for inequality B
case B) [tex]\$9[/tex]
Substitute the value of x in the inequality A and in the inequality B to verify
Verify inequality A
[tex]9<9[/tex] -------> is not true
Verify inequality B
[tex]9\geq14[/tex] ------> is not true
Therefore
[tex]\$9[/tex] is not a possible value for x
case C) [tex]\$11[/tex]
Substitute the value of x in the inequality A and in the inequality B to verify
Verify inequality A
[tex]11<9[/tex] -------> is not true
Verify inequality B
[tex]11\geq14[/tex] ------> is not true
Therefore
[tex]\$11[/tex] is not a possible value for x
case D) [tex]\$13[/tex]
Substitute the value of x in the inequality A and in the inequality B to verify
Verify inequality A
[tex]13<9[/tex] -------> is not true
Verify inequality B
[tex]13\geq14[/tex] ------> is not true
Therefore
[tex]\$13[/tex] is not a possible value for x
case E) [tex]\$14[/tex]
Substitute the value of x in the inequality A and in the inequality B to verify
Verify inequality A
[tex]14<9[/tex] -------> is not true
Verify inequality B
[tex]14\geq14[/tex] ------> is true
Therefore
[tex]\$14[/tex] is a possible value for x
case F) [tex]\$15[/tex]
Substitute the value of x in the inequality A and in the inequality B to verify
Verify inequality A
[tex]15<9[/tex] -------> is not true
Verify inequality B
[tex]15\geq14[/tex] ------> is true
Therefore
[tex]\$15[/tex] is a possible value for x
therefore
the answer is
[tex]\$8[/tex]
[tex]\$14[/tex]
[tex]\$15[/tex]