Respuesta :

Answer:

[tex]x=-3+\sqrt{3}[/tex]    , [tex]x=-3-\sqrt{3}[/tex]

Step-by-step explanation:

x2 + 6x + 7 = 0

Solve the equation for x

To solve this we apply quadratic formula

[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]

a= 1 , b= 6 , c= 7

Plug in all the values in the formula

[tex]x=\frac{-6+-\sqrt{6^2-4(1)(7)} }{2(1)}[/tex]

[tex]x=\frac{-6+-\sqrt{36-28} }{2(1)}[/tex]

[tex]x=\frac{-6+-\sqrt{8} }{2(1)}[/tex]

[tex]x=\frac{-6+-2\sqrt{2} }{2}[/tex]

Divide each term by 2

[tex]x=-3+- \sqrt{3}[/tex]

so we got two value for x

[tex]x=-3+\sqrt{3}[/tex]    , [tex]x=-3-\sqrt{3}[/tex]