Answer:
[tex]x=-3+\sqrt{3}[/tex] , [tex]x=-3-\sqrt{3}[/tex]
Step-by-step explanation:
x2 + 6x + 7 = 0
Solve the equation for x
To solve this we apply quadratic formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
a= 1 , b= 6 , c= 7
Plug in all the values in the formula
[tex]x=\frac{-6+-\sqrt{6^2-4(1)(7)} }{2(1)}[/tex]
[tex]x=\frac{-6+-\sqrt{36-28} }{2(1)}[/tex]
[tex]x=\frac{-6+-\sqrt{8} }{2(1)}[/tex]
[tex]x=\frac{-6+-2\sqrt{2} }{2}[/tex]
Divide each term by 2
[tex]x=-3+- \sqrt{3}[/tex]
so we got two value for x
[tex]x=-3+\sqrt{3}[/tex] , [tex]x=-3-\sqrt{3}[/tex]