Question

A gas has a volume of 5.0 L at a pressure of 50 kPa. What happens to the volume when temperature is held constant and the pressure is increased to 125 kPa?

Answer 1

The answer is 2L have a great day:)

Answer 2

Answer:

Volume will be 2L

Explanation:

The problem can be solved taking into account Boyle-Mariotte Law for ideal gases

. It states:

At constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts.

$P_{1} *V_{1} =P_{2} *V_{2}$

Being P1 and V1 the values of Pressure an temperature in the gas initial state. And P2, V2, pressure and temperature of the gas in the final state.

The given values are:

• V1=5L
• P1=50kPa
• P2=125kPa
• V2=?

So, we replace given values in the formula isolating V2:

$\frac{P_{1} *V_{1}}{P_{2} } =V_{2}\\\\\frac{50kPa *5L}{125kPa}=V_{2}\\\\V_{2}=2L$

So, the volume when pressure is increased to 125 kPa will be 2L.