Write an equation for the line that is parallel to the given line and that passes through the given point.
y equals five halves x minus 10; the point negative 6, negative 29


A. y equals five halves x plus one hundred thirty three halves

B. y equals five halves x minus 14

C. y equals two fifths x minus 14

D. y equals negative two fives x plus 14


Respuesta :

Answer:

The correct option is B.

Step-by-step explanation:

The slope intercept form of a line is

[tex]y=mx+b[/tex]

where, m is slope and b is y-intercept.

The given equation is

[tex]y=\frac{5}{2}x-10[/tex]

It means the slope of the line is 5/2 and y-intercept is -10.

The slope of two parallel lines is same. So, the slope of required line is 5/2.

The equation of required line is

[tex]y=\frac{5}{2}x+b[/tex]

It is given that the line passes through the point (-6,-29).

[tex](-29)=\frac{5}{2}(-6)+b[/tex]

[tex]-29=-15+b[/tex]

[tex]-29+15=+b[/tex]

[tex]-14=b[/tex]

The y-intercept of required line is -14. So the equation of required line is

[tex]y=\frac{5}{2}x-14[/tex]

Therefore the correct option is B.

Answer:

the answer is  B. y equals five halves x minus 14

Step-by-step explanation:

hope it helps