Question

During a particular baseball​ season, a team averaged​ 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of​ 9,440 per game. what is the probability that a randomly selected game during the season had an attendance greater than​ 50,000 people?

Answer 1

Given:
μ = 41,602, the mean
σ = 9,440, the standard deviation.

For the random variable x = 50,000, the z-score is
z = (x - μ)/ο = (50,000 - 41,602)/9,440 = 0.8896

From standard tables, obtain
P(x > 50,000) = 0.08132 or 81.32%

Answer: 0.8132