contestada

If y varies directly as x and y is 18 when x is 5 which expression can be used to find the value of y when x is 11?

Respuesta :

y = kx  where k is a constant   Thats direct variation.

plug in given values:-

18  = k * 5

k = 18/5 = 3.6

so the equation of variation is y = 3.6x

when x = 11, y = 3.6 * 11 =  39.6  Answer

Answer:

The value of y is [tex]\frac{198}{5}[/tex] or 39.6.

Step-by-step explanation:

It is given that y varies directly as x and y. It means y is directly proportional to x.

[tex]y\propto x[/tex]

[tex]y=kx[/tex]            .... (1)

where, k is constant of proportionality.

It is given that y is 18 when x is 5.

Substitute y=18 and x=5 in equation (1).

[tex]18=k(5)[/tex]

Divide both sides by 5.

[tex]\frac{18}{5}=k[/tex]

The value of k is [tex]\frac{18}{5}[/tex]. So, the relation between x and y is

[tex]y=\frac{18}{5}x[/tex]            .... (2)

We need to find the value of y when x=11.

[tex]y=\frac{18}{5}(11)[/tex]

[tex]y=\frac{198}{5}[/tex]

[tex]y=39.6[/tex]

Therefore the value of y is [tex]\frac{198}{5}[/tex] or 39.6.