Respuesta :
4= let 1st angle = x
so the 2nd angle = 180 - x (because they are supplementary)
1st angle = 2 times of 2nd angle
x = 2(180 - x)
x = 360 - 2x
x + 2x = 360
3x = 360
x = 360/3
x = 120
so, the 1st angle = x = 120 degrees
and the 2nd angle = 180 - x = 180 - 120 = 60 degrees
working on 5 now
so the 2nd angle = 180 - x (because they are supplementary)
1st angle = 2 times of 2nd angle
x = 2(180 - x)
x = 360 - 2x
x + 2x = 360
3x = 360
x = 360/3
x = 120
so, the 1st angle = x = 120 degrees
and the 2nd angle = 180 - x = 180 - 120 = 60 degrees
working on 5 now
Supplementary angles are two angles that add up to 180°. 180÷3=60. 60*2=120. 120+60=160.
m∠A=60° and m∠B=120°.
This question is talking about vertical angles. One of the angles is 127°, so the one opposite to it is also 127° (look up vertical angles if you don't understand).
I don't know how to find the other two angles though.
m∠A=60° and m∠B=120°.
This question is talking about vertical angles. One of the angles is 127°, so the one opposite to it is also 127° (look up vertical angles if you don't understand).
I don't know how to find the other two angles though.